-10v^2+v+44=0

Solution for -10v^2+v+44=0 equation:

-10v^2+v+44=0

a = -10; b = 1; c = +44;
Δ = b2-4ac
Δ = 12-4·(-10)·44
Δ = 1761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1761}}{2*-10}=\frac{-1-\sqrt{1761}}{-20}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1761}}{2*-10}=\frac{-1+\sqrt{1761}}{-20}
$